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Urea (CH4N2O) is a common fertilizer that cab be synthesized by the reaction of ammonia with carbon dioxide ac?

Urea (CH4N2O) is a common fertilizer that cab be synthesized by the reaction of ammonia with carbon dioxide according to the following equation: NH3 + CO2 --> CH4N2O + H2O (equation not balanced) In an industrial synthesis, 43.0kg of urea was obtained when 34.0kg of ammonia was reacted with 50.0kg of carbon dioxide. Determine the limiting reactant and calculate the percent yield of the reaction.

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1. balance the equation 2NH3 + CO2 --> CH4N2O + H2O in order to determine the limiting reactant, divide the number of moles of each reactants by its coefficient in the balanced equation. smallest result belongs to the limiting reactant. moles ammonia = mass / molar mass = 34000g / 17.0g/mol = 2000 moles divided by coefficient 2000 moles / 2 = 1000 moles moles carbon dioxide = 50000g / 44.0g/mol = 1140 moles divided by coefficient = 1140 moles limiting reactant is ammonia moles urea = (1/2) * moles ammonia = 1000moles/2 = 500moles which has a mass of 500 moles * 60.1g/mol = 30100g percent yield = ( experimental yield / theoretical yield ) * 100% = ( 43000g / 30100g ) * 100% = 143% this not possible.. it indicates an error in the given data can you tell me how to make a big avatar like that?