I can't find this volume...!?
Urea, NH2CONH2, is a nitrogen fertilizer that is manufactured from ammonia and carbon dioxide. 2 NH3(g) + CO2(g) NH2CONH2(aq) + H2O(l) What volume of ammonia at 25°C and 1.60 atm is needed to produce 908 g (2 lb) of urea?
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- First convert grams to moles: 908 g x (1 mol / 60g) = 15.1 mol urea Then convert from moles urea to moles NH3: 15.1 mol urea x (2 mol NH3 / 1 mol urea) = 30.2 mol NH3 Finally plug in the moles of NH3 into the ideal gas law, and solve for volume: V = nRT/P = (30.2 mol)(0.0821)(298 K)/(1.6 atm) = 462 L
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