The Grass Doctor

chem question 2 help?

urea (NH2)2 CO is used for fertilizer. calculate the number of N, C, O, H atoms in 1.68x10^4 grams of urea. Pls explin how to solve it

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1. Moles = mass / molar mass = 1.68 x10^4 g / 60.07 g/mol =276.8 Moles N = 2 x 276.8 = 553.6 Atoms = 553.6 x 6.02 x 10^23 =3.33 x 10^26 Moles H = 4 x 276.8 = 1107.2 atoms = 1107.2 x 6.02 x 10^23 =6.67 x 10^26 Moles C = moles O = 276.8 atoms = 276.8 x 6.02 x 10^23 =1.67 x 10^26